(x+2)(x^2-4x+2)=0

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Solution for (x+2)(x^2-4x+2)=0 equation: 


Simplifying
(x + 2)(x2 + -4x + 2) = 0

Reorder the terms:
(2 + x)(x2 + -4x + 2) = 0

Reorder the terms:
(2 + x)(2 + -4x + x2) = 0

Multiply (2 + x) * (2 + -4x + x2)
(2(2 + -4x + x2) + x(2 + -4x + x2)) = 0
((2 * 2 + -4x * 2 + x2 * 2) + x(2 + -4x + x2)) = 0
((4 + -8x + 2x2) + x(2 + -4x + x2)) = 0
(4 + -8x + 2x2 + (2 * x + -4x * x + x2 * x)) = 0
(4 + -8x + 2x2 + (2x + -4x2 + x3)) = 0

Reorder the terms:
(4 + -8x + 2x + 2x2 + -4x2 + x3) = 0

Combine like terms: -8x + 2x = -6x
(4 + -6x + 2x2 + -4x2 + x3) = 0

Combine like terms: 2x2 + -4x2 = -2x2
(4 + -6x + -2x2 + x3) = 0

Solving
4 + -6x + -2x2 + x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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